September 28, 2004
More about sex linked genes
We went over a couple more problems about sex-linked
traits:
(See Fig. 11.13b Pedigree of Queen Victoria (III-2) and her
descendants, showing the X-linked recessive inheritance of
hemophilia)
Question:
In 1995, a sixty-three year old man named Eugene Romanov, a
resident of the former Soviet Union, turned up. He shared both
the disease and last name; claimed to be the grandson of Anastasia,
daughter of Czar Nikolas II.
(Said Anastasia (whose body was never found) was raised by a
farmer, and later she married a nephew of her adopted parents and
had a daughter, Eugene's mother.)
Draw the pedigree corresponding to his story, and
figure out how to determine who might be a carrier of the
hemophilia gene.
Another Question
White eyes (w) is a recessive gene on the X chromosome of
Drosophila melanogaster and ebony body (eb) is a
recessive gene on an autosome.
A true breeding white-eyed female with normal body is crossed to
a normal-eyed, ebony male (to make an F1).
How would you notate this cross?
What is/are the phenotypes of the F1?
Now the F1 are intercrossed to make an F2 generation.
What are the expected phenotypes?
We did this one in class. The secret is to
"divide and conquer". Solve for the phenotypes of each
locus separately and the multiply the probabilities for the two
loci. The autosomal locus is the same as before. For the
sex-linked locus you have to keep track of males and females
separately.
Incomplete dominance
Heterozygous snapdragons are pink
RR = red, Rr = pink, rr = white
Cross Red x white
F1 = ??
F2 = ??
Nothing fancy here. It simply means that
heterozygotes are intermediate and three phenotypic classes are
possible.
Make sure you understand why the F2 will have a 1:2:1
ratio
Codominance means both alleles are
expressed
Example: blood groups
Degrees of Dominance
A single gene can show different kinds of dominance, depending
on the scale at which you look
Example: Smooth/Wrinkled peas is a result of starch production
in the peas.
(Starch grains absorb water which makes the pea swell. When
too little starch is present the peas don't swell and look
wrinkled).
This is true of almost all genes. At the molecular
level any allele is codominant. Thus dominance is not an intrinsic
property of genes. Instead it is just a shorthand way of saying
that we can't distinguish the different gene effects when we
look at the organism.
Multiple alleles
In a large population, lots of genetic variation is present.
Most of it is not expressed; occasionally you find a mutant with
obvious phenotype.
Still, well studied genes show lots of variation (e.g. sickle
cell: you book gives a table of about 15 different alleles in
Chapter 4).
How does that affect inheritance?
Example with multiple alleles: Rabbit coat color
Variation at a single locus
C>cch>ch>c (normal, chinchilla,
Himalayan, albino)
Different defects in the pigment gene
What do you see in these crosses:
Composite cross:
Normal x Himalayan
and
Chinchilla x albino
Now cross the two F1s
What are the phenotypic ratios in the
F2?
We solved this cross in class. The trick is to
realize that each individual rabbit still only has two alleles of
the gene. Figure out what gametes mom and dad can make, then
combine them to figure out the genotypes of the F2. Then use the
dominance relationships (above) to get the
phenotypes.
See http://home.pacbell.net/bettychu/genetics.html
for more about rabbit color genes
Epistasis
Gene interactions may modify the phenotypic
ratios
Example:
Agouti, albino and black mice: two genes give only three F2
phenotypes
(A-/C-, --/cc, aa/C-)
This is because cc blocks all pigment, so it doesn't matter
what the genotype at A is.
Your book says there is also a third interacting
gene. Black (B) is dominant to brown (b). What would you expect
from the trihybrid cross
AaBbCc x AaBbCc?
Another example
Black Lab x Yellow Lab
Two genes:
B determines types of pigment (B=black, b=brown or
chocolate)
E determines deposition of pigment on hair (E = pigment on
hairs, e = none)
Cross BBEE x bbee
F1 = ??
F2 = 9:4:3 (black:yellow:brown)
e is epistatic to B and b
Notice that both of these examples are cases where
knocking out a gene early in a metabolic pathway blocks the
expression of later genes (i.e. if they can't make any pigment
in the first place, genes that affect the patterning of color
don't matter).
Sets of genes in a common metabolic pathway often
show epistasis.
Redundant genes
Fruit shape in Shepherd's Purse
Most plants have triangular fruits; occasionally you find a
plant with round fruits.
Cross Round x Triangular
F1: all Triangular
F2: 1/16 round, all the rest triangular
Propose a mechanism to explain those
results
Epistasis: things to remember:
The genes are inherited just as before, and the genotypic
ratios in the F1 and F2 are just the same.
The interaction of gene products can affect the
phenotypes, but the genes are still genes, following the same
rules.
Don't try to memorize all of the different ratios (12:3:1,
9:6, etc). Instead, relate them back to combinations of the
familiar 9:3:3:1
Here are two final examples:
White squash x green squash
F2 gives 12:3:1 white, yellow, green
Why?
White flowers in morning glories
Anthocyanin pathway has several different steps that can be
blocked
Determines white/red/purple flowers
White flowers can arise from defects in in several different
genes (e.g. DFR and ANS)
Cross two purple morning glories and see 9:7 purple:white
offspring-
How can that happen? Again, relate that back to the
9:3:3:1 ratio to figure out which genotypes must be in each
phenotypic class.
Chapter 11 problems
2, 3, 4, 6, 12, 16, 17, 18, 21, 25